Application of Coordination Compounds & Organometallic Compound Importance of co-ordination compounds (in qualitative analysis, extraction of metals and in biological systems).: NEET MCQs with Answers
15 free questions on Application of Coordination Compounds & Organometallic Compound Importance of co-ordination compounds (in qualitative analysis, extraction of metals and in biological systems). for NEET (UG), starting with previous-year NEET and AIPMT questions. Try each one, then tap Show answer for the answer and a short explanation.
Question 1
Previous-year questionAmong the following, which is not a π-bonded organometallic compound? [AIPMT 2003]
- (CH₃)₄Sn
- K[PtCl₃(η²—C₂H₄)]
- Fe(η⁵—C₅H₅)₂
- Cr(η⁶—C₆H₆)₂
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Answer: (A) (CH₃)₄Sn
Explanation: The hapticity symbol η followed by a number tells you how many carbon atoms of the ligand are bound simultaneously to the metal, and its presence is the signature of π-bonding. (CH₃)₄Sn has no η notation. Each methyl group is joined to tin by an ordinary two-electron σ-bond through a single carbon, so tetramethyltin is a σ-bonded organometallic compound and the odd one out. The others are all π-bonded: K[PtCl₃(η²—C₂H₄)] is Zeise's salt, with two carbons of ethene bound side-on; Fe(η⁵—C₅H₅)₂ is ferrocene, with all five carbons of each cyclopentadienyl ring bound; and Cr(η⁶—C₆H₆)₂ is dibenzenechromium, with all six carbons of each benzene ring bound.
Question 2
Previous-year questionWhich of the following is considered to be an anticancer species? [AIPMT 2004]
- Dichlorido(η²-ethene)platinum(II)
- Tetrachloridoplatinate(II)
- cis-Diamminedichloridoplatinum(II)
- trans-Diamminedichloridoplatinum(II)
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Answer: (C) cis-Diamminedichloridoplatinum(II)
Explanation: The structure required is the one with two ammine ligands on adjacent corners of the square plane and two chlorido ligands on the other two, that is cis-[Pt(NH₃)₂Cl₂], cisplatin. Inside the cell the two chloride ligands are displaced by water and the platinum then binds to the N7 atoms of two neighbouring guanine bases in DNA. That intrastrand cross-link distorts the double helix and prevents replication, killing the rapidly dividing tumour cell. The trans isomer has its two chlorides 180° apart, cannot bridge two adjacent bases and is inactive. The ethene complex and tetrachloridoplatinate(II) contain no ammine ligands at all and are not anticancer agents.
Question 3
Previous-year questionIron carbonyl, [Fe(CO)₅], is [NEET 2018]
- tetranuclear
- mononuclear
- dinuclear
- trinuclear
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Answer: (B) mononuclear
Explanation: The formula contains only one iron atom, so the carbonyl is mononuclear. It has a trigonal bipyramidal shape with all five CO groups bonded terminally to that single metal centre.
Question 4
Previous-year questionAn example of a sigma-bonded organometallic compound is [NEET 2017]
- Grignard reagent
- ferrocene
- cobaltocene
- ruthenocene
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Answer: (A) Grignard reagent
Explanation: In RMgX the alkyl group is joined to magnesium by a straightforward two-electron sigma bond. Ferrocene, cobaltocene and ruthenocene are pi-bonded sandwich compounds in which the cyclopentadienyl rings donate pi electron density.
Question 5
Previous-year questionHgCl₂ and I₂ are both dissolved in water containing I⁻ ions. The pair of species formed is [NEET 2017]
- HgI₂ and I⁻
- [HgI₄]²⁻ and I₃⁻
- Hg₂I₂ and I⁻
- HgI₂ and I₃⁻
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Answer: (B) [HgI₄]²⁻ and I₃⁻
Explanation: Excess iodide converts mercury(II) chloride into the soluble tetraiodomercurate(II) complex, [HgI₄]²⁻, while iodine itself combines with iodide to give the triiodide ion, I₃⁻.
Question 6
Previous-year questionWhich complex of platinum is used as an anti-cancer agent? [AIPMT 2014]
- mer-[Co(NH₃)₃Cl₃]
- cis-[PtCl₂(NH₃)₂]
- cis-K₂[PtCl₂Br₂]
- Na₂CoCl₄
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Answer: (B) cis-[PtCl₂(NH₃)₂]
Explanation: cis-Diamminedichloridoplatinum(II), cisplatin, is a standard anticancer drug. It cross-links guanine bases of DNA and thereby prevents cell division; the trans isomer is ineffective.
Question 7
Previous-year questionIn a metal carbonyl of general formula M(CO)ₓ, where M = metal and x = 4, the metal is bonded to [AIPMT 1995]
- carbon and oxygen
- C≡O
- oxygen
- carbon
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Answer: (D) carbon
Explanation: In every metal carbonyl the ligand attaches through its carbon atom, never through oxygen. The reason is that the highest occupied molecular orbital of CO is concentrated on the carbon, so it is the carbon lone pair that is donated to the metal to form the σ-bond. The π-component of the bonding also runs through carbon: the metal donates electron density back into the π* orbital of CO, which again has its larger coefficient on the carbon atom. So the metal is bonded to carbon alone, and the linkage is written M—C≡O.
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Question 8
Previous-year questionWhich of the following organometallic compounds is both σ and π-bonded? [AIPMT 2001]
- [Fe(η⁵—C₅H₅)₂]
- K[PtCl₃(η²—C₂H₄)]
- [Co(CO)₅NH₃]²⁺
- Fe(CH₃)₃
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Answer: (C) [Co(CO)₅NH₃]²⁺
Explanation: Metal carbonyls are the standard example of simultaneous σ and π bonding. Each CO ligand donates its carbon lone pair into a vacant metal hybrid orbital to form a σ-bond, and the metal then returns electron density from a filled d-orbital into the vacant π* orbital of CO to form a π-bond. The two interactions reinforce each other and are described as synergic. In [Co(CO)₅NH₃]²⁺ the cobalt is bound to five CO ligands in this σ-plus-π fashion, together with an ammonia ligand that is a pure σ-donor. Ferrocene is purely π-bonded, Zeise's salt is π-bonded through the ethene, and Fe(CH₃)₃ is purely σ-bonded.
Question 9
Previous-year questionWhich of the following carbonyls will have the strongest C—O bond? [AIPMT 2011]
- [Mn(CO)₆]⁺
- [Cr(CO)₆]
- [V(CO)₆]⁻
- [Fe(CO)₅]
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Answer: (A) [Mn(CO)₆]⁺
Explanation: A positive charge on the complex lowers the electron density available on the metal for back-donation into the π* orbitals of CO. Less back-bonding leaves the C—O bond closest to free CO, so the cationic [Mn(CO)₆]⁺ has the strongest C—O bond.
Question 10
Previous-year questionThe correct order of the trans-effect of the following species is [NEET 2016 Phase II]
- NH₃ > CN⁻ > Br⁻ > C₆H₅⁻
- CN⁻ > C₆H₅⁻ > Br⁻ > NH₃
- Br⁻ > CN⁻ > NH₃ > C₆H₅⁻
- CN⁻ > Br⁻ > C₆H₅⁻ > NH₃
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Answer: (B) CN⁻ > C₆H₅⁻ > Br⁻ > NH₃
Explanation: The trans-effect is the ability of a coordinated ligand to labilise the group directly trans to itself, speeding up its substitution in a square-planar complex. Ligands that are strong π-acceptors or strong σ-donors exert the greatest trans-effect. The established series places CN⁻ and CO at the top, followed by strongly σ-donating carbon ligands such as phenyl, then the heavier halides, with N-donors like NH₃ near the bottom: CN⁻ > C₆H₅⁻ > Br⁻ > NH₃ The trans-effect is of real synthetic value — it is what allows cisplatin and transplatin to be prepared selectively from the same starting materials.
Question 11
Previous-year questionWhich of the following has the longest C—O bond length? (Free C—O bond length in CO is 1.128 Å) [NEET 2016]
- [Ni(CO)₄]
- [Co(CO)₄]⁻
- [Fe(CO)₄]²⁻
- [Mn(CO)₆]⁺
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Answer: (C) [Fe(CO)₄]²⁻
Explanation: The C—O bond length in a carbonyl is governed by synergic π-back-bonding. The metal donates electron density from its filled d-orbitals into the vacant π* antibonding orbitals of CO. Filling an antibonding orbital weakens and therefore lengthens the C—O bond. The more negative the charge on the complex, the greater the electron density available on the metal, and so the more extensive the back-bonding. Ranking by charge: [Fe(CO)₄]²⁻ (−2) > [Co(CO)₄]⁻ (−1) > [Ni(CO)₄] (0) > [Mn(CO)₆]⁺ (+1) Hence [Fe(CO)₄]²⁻ has the weakest and longest C—O bond. Note that stronger back-bonding lengthens C—O while simultaneously shortening and strengthening the M—C bond.
Question 12
Previous-year questionAn example of a sigma bonded organometallic compound is [NEET 2017]
- Grignard's reagent
- ferrocene
- cobaltocene
- ruthenocene
Show answer
Answer: (A) Grignard's reagent
Explanation: A Grignard reagent, RMgX (for example CH₃MgBr), contains a direct two-electron covalent σ-bond between the carbon of the alkyl group and the magnesium atom. That single localised M—C bond is exactly what defines a σ-bonded organometallic compound. Ferrocene, cobaltocene and ruthenocene are all metallocenes of the type M(η⁵-C₅H₅)₂. In these the metal sits between two cyclopentadienyl rings and is bound to the delocalised π-electron cloud of each ring rather than to any one carbon atom, so they are π-bonded organometallic compounds.
Question 13
In chelate therapy, a metal present in toxic proportion is removed by forming a coordination compound. Which pair of chelating ligands is used to remove excess copper and iron?
- cis-platin and ethane-1,2-diamine
- Dimethylglyoxime and glycinate
- Cyanocobalamine and oxalate
- D-penicillamine and desferrioxime B
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Answer: (D) D-penicillamine and desferrioxime B
Explanation: Excess copper and iron are removed by the chelating ligands D-penicillamine and desferrioxime B through the formation of coordination compounds. EDTA is used in a similar way in lead poisoning. cis-platin is a platinum complex that inhibits the growth of tumours, and cyanocobalamine is vitamin B₁₂, so neither is a chelating drug for metal removal.
Question 14
Dimethylglyoxime is added to a solution of Ni²⁺ made ammoniacal, and a rosy red solid separates. Which description of this detection reaction is correct?
- Neutral dimethylglyoxime binds through its two oxygen atoms and gives the soluble cation [Ni(dmgH₂)₂]²⁺
- Each dimethylglyoxime molecule loses a proton in the ammoniacal medium and binds Ni²⁺ as a bidentate anion through nitrogen, giving the neutral chelate [Ni(dmg)₂]
- Ammonia replaces the water ligands of Ni²⁺, and the red solid is [Ni(NH₃)₆]²⁺ with dimethylglyoxime acting only as a precipitating anion
- Dimethylglyoxime oxidises Ni²⁺ to Ni³⁺, and the red solid is a simple hydrated oxide of nickel(III)
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Answer: (B) Each dimethylglyoxime molecule loses a proton in the ammoniacal medium and binds Ni²⁺ as a bidentate anion through nitrogen, giving the neutral chelate [Ni(dmg)₂]
Explanation: The ammoniacal medium removes one proton from each dimethylglyoxime molecule to give the dimethylglyoximate anion. Two such anions chelate Ni²⁺ through their nitrogen atoms. The charges cancel, so the chelate [Ni(dmg)₂] is neutral and separates as a rosy red precipitate, which makes it useful for detecting nickel.
Question 15
How do decacarbonyldimanganese(0) and octacarbonyldicobalt(0) differ in the way their two metal centres are linked?
- Mn₂(CO)₁₀ has a direct Mn–Mn bond with no bridging CO, whereas Co₂(CO)₈ has a Co–Co bond bridged by two CO groups
- Both have a metal–metal bond bridged by two CO groups and differ only in the number of terminal CO groups
- Mn₂(CO)₁₀ has a Mn–Mn bond bridged by two CO groups, whereas Co₂(CO)₈ has a direct Co–Co bond with no bridging CO
- Neither has a metal–metal bond; the two metal centres in each are held together only by bridging CO groups
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Answer: (A) Mn₂(CO)₁₀ has a direct Mn–Mn bond with no bridging CO, whereas Co₂(CO)₈ has a Co–Co bond bridged by two CO groups
Explanation: Mn₂(CO)₁₀ is made of two square pyramidal Mn(CO)₅ units joined by a Mn–Mn bond, so all ten CO groups are terminal. Co₂(CO)₈ has a Co–Co bond that is also bridged by two CO groups, leaving six terminal CO groups.
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